(8x-3)(x^2-3x-1)=0

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Solution for (8x-3)(x^2-3x-1)=0 equation: 


Simplifying
(8x + -3)(x2 + -3x + -1) = 0

Reorder the terms:
(-3 + 8x)(x2 + -3x + -1) = 0

Reorder the terms:
(-3 + 8x)(-1 + -3x + x2) = 0

Multiply (-3 + 8x) * (-1 + -3x + x2)
(-3(-1 + -3x + x2) + 8x * (-1 + -3x + x2)) = 0
((-1 * -3 + -3x * -3 + x2 * -3) + 8x * (-1 + -3x + x2)) = 0
((3 + 9x + -3x2) + 8x * (-1 + -3x + x2)) = 0
(3 + 9x + -3x2 + (-1 * 8x + -3x * 8x + x2 * 8x)) = 0
(3 + 9x + -3x2 + (-8x + -24x2 + 8x3)) = 0

Reorder the terms:
(3 + 9x + -8x + -3x2 + -24x2 + 8x3) = 0

Combine like terms: 9x + -8x = 1x
(3 + 1x + -3x2 + -24x2 + 8x3) = 0

Combine like terms: -3x2 + -24x2 = -27x2
(3 + 1x + -27x2 + 8x3) = 0

Solving
3 + 1x + -27x2 + 8x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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